(Start on a new page.)

A pendulum with a bob of mass 5 kg is held stationary at a height h metres above the ground. When released, it collides with a block of mass 2 kg which is stationary at point **A**.

The bob swings past **A **and comes to rest momentarily at a position ¼ h above the ground.

The diagrams below are NOT drawn to scale

Immediately after the collision the 2 kg block begins to move from **A** to **B** at a constant speed of 4,95 m∙s^{-1}. Ignore frictional effects and assume that no loss of mechanical energy occurs during the collision.

5.1 Calculate the:

5.1.1 Kinetic energy of the block immediately after the collision (3)

5.1.2 Height h (4)

The block moves from point **B** at a velocity of 4,95 m·s^{-1} up a rough inclined plane to point **C**. The speed of the block at point **C **is 2 m·s^{-1.} Point **C **is 0,5 m above the horizontal, as shown in the diagram below.

During its motion from **B **to **C **a uniform frictional force acts on the block.

5.2 State the work-energy theorem in words. (2)

5.3 Use energy principles to calculate the work done by the frictional force when the 2 kg block moves from point B to point C. (4)

**[13]**